PUZZLE 4.0.2 Type of analysis: tree reconstruction Parameter estimation: approximate (faster) Parameter estimation uses: neighbor-joining tree (for substitution process and rate variation) Standard errors (S.E.) are obtained by the curvature method. The upper and lower bounds of an approximate 95% confidence interval for parameter or branch length x are x-1.96*S.E. and x+1.96*S.E. SEQUENCE ALIGNMENT Input data: 5 sequences with 705 amino acid sites Number of constant sites: 5 (= 0.7% of all sites) SUBSTITUTION PROCESS Model of substitution: JTT (Jones et al. 1992) Amino acid frequencies (estimated from data set): pi(A) = 6.1% pi(R) = 6.9% pi(N) = 5.1% pi(D) = 6.3% pi(C) = 0.8% pi(Q) = 3.7% pi(E) = 5.5% pi(G) = 6.1% pi(H) = 1.6% pi(I) = 5.6% pi(L) = 8.9% pi(K) = 4.3% pi(M) = 2.0% pi(F) = 4.1% pi(P) = 7.0% pi(S) = 7.7% pi(T) = 7.1% pi(W) = 1.1% pi(Y) = 3.2% pi(V) = 6.9% RATE HETEROGENEITY Model of rate heterogeneity: Gamma distributed rates Gamma distribution parameter alpha (estimated from data set): 1.40 (S.E. 0.12) Number of Gamma rate categories: 8 Rates and their respective probabilities used in the likelihood function: Category Relative rate Probability 1 0.1282 0.1250 2 0.3095 0.1250 3 0.4898 0.1250 4 0.6888 0.1250 5 0.9240 0.1250 6 1.2249 0.1250 7 1.6640 0.1250 8 2.5707 0.1250 Categories 1-8 approximate a continous Gamma-distribution with expectation 1 and variance 0.71. Combination of categories that contributes the most to the likelihood (computation done without clock assumption assuming quartet-puzzling tree): 2 1 1 8 8 2 1 1 1 1 1 1 1 1 1 1 1 8 8 1 1 8 1 8 8 2 8 8 8 8 8 8 2 1 8 1 8 1 1 8 1 1 2 1 8 1 8 1 1 1 1 1 8 8 1 2 1 8 3 1 1 8 4 3 8 1 3 1 8 2 1 8 1 2 8 8 8 1 1 8 1 8 1 8 3 8 2 8 8 8 1 1 8 8 3 6 8 1 8 4 2 5 1 8 3 3 3 2 6 8 2 8 8 8 1 8 6 8 1 5 8 2 1 1 1 1 8 1 1 1 1 6 1 1 1 2 2 1 8 1 1 1 1 1 1 1 8 2 6 1 5 7 8 1 6 2 1 8 1 8 1 1 1 8 1 1 1 1 1 1 8 1 1 8 1 1 1 8 2 1 1 1 4 5 2 1 2 1 8 8 1 6 3 2 1 8 2 3 8 3 3 2 2 8 1 8 2 2 8 4 2 2 1 1 1 8 8 5 8 3 8 2 1 1 1 1 1 1 8 8 3 2 3 8 4 3 8 8 2 8 3 2 7 4 3 4 2 4 7 6 8 8 8 8 8 2 1 1 1 1 1 1 8 8 8 8 1 8 8 8 2 8 3 8 8 1 8 8 1 4 8 1 4 2 3 3 8 8 8 6 8 8 8 8 8 8 8 8 3 8 8 2 6 6 1 7 6 4 8 8 1 8 8 6 6 1 1 2 3 8 8 2 3 8 7 8 6 1 5 8 3 1 1 8 8 8 8 8 5 3 2 2 2 8 1 3 8 4 2 1 4 4 8 8 7 3 8 1 8 8 3 2 8 1 1 8 1 1 8 8 8 1 5 4 1 6 8 2 6 5 8 3 8 7 2 8 8 2 8 8 8 8 4 2 1 3 8 7 8 2 2 1 2 1 1 1 1 1 6 8 4 7 1 8 8 1 2 1 8 7 8 8 8 2 8 8 2 1 8 1 3 5 8 1 2 1 1 8 3 4 4 3 2 8 2 8 8 3 1 8 8 5 2 1 8 3 2 1 1 1 2 1 6 3 8 8 8 1 8 3 2 2 6 8 7 3 1 1 1 1 1 1 1 1 1 1 1 1 1 1 8 8 2 6 3 1 2 4 1 1 3 6 8 8 8 2 8 5 8 3 6 3 8 8 8 6 8 7 8 2 8 8 8 8 2 1 1 1 1 1 1 1 1 1 1 1 1 8 6 1 8 4 6 8 1 2 4 1 2 1 1 1 3 1 4 2 1 1 1 1 3 2 4 8 4 1 3 1 2 8 2 3 4 1 2 1 1 5 4 7 2 4 8 8 3 1 8 2 2 8 7 5 5 6 8 1 8 2 8 3 8 8 2 8 8 8 8 3 1 2 8 6 2 8 8 8 5 3 3 1 1 8 8 2 1 8 5 1 8 8 1 8 3 8 7 4 7 2 8 8 2 1 1 8 8 1 1 1 8 1 8 2 2 1 2 8 1 1 1 1 2 8 8 1 8 1 8 8 8 1 1 8 1 1 1 8 8 8 8 8 1 1 1 1 1 8 8 2 2 8 8 1 1 1 8 1 8 8 1 8 1 8 8 8 1 SEQUENCES IN INPUT ORDER 5% chi-square test p-value Saccharomy passed 10.71% [0] Saccharom2 passed 34.97% [0] Deinococcu failed 0.00% [0] Deinococc2 failed 0.02% [0] Schizosacc passed 22.84% [0] The chi-square tests compares the amino acid composition of each sequence to the frequency distribution assumed in the maximum likelihood model. The number in square brackets indicates how often each sequence is involved in one of the 0 completely unresolved quartets of the quartet puzzling tree search. IDENTICAL SEQUENCES The sequences in each of the following groups are all identical. To speed up computation please remove all but one of each group from the data set. Saccharomy, Saccharom2. MAXIMUM LIKELIHOOD DISTANCES Maximum likelihood distances are computed using the selected model of substitution and rate heterogeneity. 5 Saccharomy 0.00000 0.00000 6.07107 8.99822 8.99901 Saccharom2 0.00000 0.00000 6.07107 8.99822 8.99836 Deinococcu 6.07107 6.07107 0.00000 2.56768 4.63049 Deinococc2 8.99822 8.99822 2.56768 0.00000 4.55257 Schizosacc 8.99901 8.99836 4.63049 4.55257 0.00000 Average distance (over all possible pairs of sequences): 5.98867 TREE SEARCH Quartet puzzling is used to choose from the possible tree topologies and to simultaneously infer support values for internal branches. Number of puzzling steps: 1000 Analysed quartets: 5 Unresolved quartets: 0 (= 0.0%) Quartet trees are based on exact maximum likelihood values using the selected model of substitution and rate heterogeneity. QUARTET PUZZLING TREE Support for the internal branches of the unrooted quartet puzzling tree topology is shown in percent. This quartet puzzling tree is completely resolved. :---Deinococc2 :100: :100: :---Schizosacc : : : :-------Deinococcu : :-----------Saccharom2 : :-----------Saccharomy Quartet puzzling tree (in CLUSTAL W notation): (Saccharomy,((Deinococc2,Schizosacc)100,Deinococcu)100,Saccharom2); BIPARTITIONS The following bipartitions occured at least once in all intermediate trees that have been generated in the 1000 puzzling steps: Bipartitions included in the quartet puzzling tree: (bipartition with sequences in input order : number of times seen) ***.. : 1000 **... : 1000 Bipartitions not included in the quartet puzzling tree: (bipartition with sequences in input order : number of times seen) None (all bipartitions are included) MAXIMUM LIKELIHOOD BRANCH LENGTHS ON QUARTET PUZZLING TREE (NO CLOCK) Branch lengths are computed using the selected model of substitution and rate heterogeneity. :----4 Deinococc2 :-----6 : :----------5 Schizosacc :--------------------7 : :--3 Deinococcu : :-2 Saccharom2 : :-1 Saccharomy branch length S.E. branch length S.E. Saccharomy 1 0.00001 0.00111 6 1.23345 0.27110 Saccharom2 2 0.00001 0.00121 7 6.20833 1.02395 Deinococcu 3 0.35533 0.24351 Deinococc2 4 1.02921 0.25935 13 iterations until convergence Schizosacc 5 3.36942 0.48111 log L: -4999.79 WARNING --- at least one brach length is close to an internal boundary! Quartet puzzling tree with maximum likelihood branch lengths (in CLUSTAL W notation): (Saccharomy:0.00001,((Deinococc2:1.02921,Schizosacc:3.36942)100:1.23345, Deinococcu:0.35533)100:6.20833,Saccharom2:0.00001); TIME STAMP Date and time: Thu Dec 02 20:41:17 1999 Runtime: 1280 seconds (= 21.3 minutes = 0.4 hours)